20y^2+21y+4=0

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Solution for 20y^2+21y+4=0 equation:


Simplifying
20y2 + 21y + 4 = 0

Reorder the terms:
4 + 21y + 20y2 = 0

Solving
4 + 21y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + 5y)(1 + 4y) = 0

Subproblem 1

Set the factor '(4 + 5y)' equal to zero and attempt to solve: Simplifying 4 + 5y = 0 Solving 4 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 5y = 0 + -4 5y = 0 + -4 Combine like terms: 0 + -4 = -4 5y = -4 Divide each side by '5'. y = -0.8 Simplifying y = -0.8

Subproblem 2

Set the factor '(1 + 4y)' equal to zero and attempt to solve: Simplifying 1 + 4y = 0 Solving 1 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4y = 0 + -1 4y = 0 + -1 Combine like terms: 0 + -1 = -1 4y = -1 Divide each side by '4'. y = -0.25 Simplifying y = -0.25

Solution

y = {-0.8, -0.25}

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